# 1. Two Sum

# YouTube Video

%[https://youtu.be/hfN4VONP4HQ] 

# \[A1\] - Brute Force

Time: O(n^2)

Space: O(1)

```python
class Solution:
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        for i in range(len(nums)):
            for j in range(i+1, len(nums)):
                if nums[i]+nums[j]==target:
                    return [i,j]
        return
```

# \[A2\] - Hash Table

Time: O(n)

Space: O(n)

```python
class Solution:
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        dict = {}
        for i,e in enumerate(nums):
            dict[e]=i
        
        for i in range(len(nums)):
            diff = target-nums[i]
            if diff in dict and i!=dict[diff]:
                return [i,dict[diff]]
        return
```

**Comment: There is another way where you can solve the problem using a single iteration. Try to do it by yourself.**