217. Contain Duplicate
LeetCode's Contains Duplicate problem checks if there are any duplicate elements in a given array, often solved using hash sets or sorting.

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LeetCode's Contains Duplicate problem checks if there are any duplicate elements in a given array, often solved using hash sets or sorting.

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[A1] - Brute Force Time: O(n^2) Space: O(n^2) class Solution: def generate(self, numRows: int) -> List[List[int]]: # Initialize the triangle with the first row pascal_triangle = [] for i in range(numRows): # S...

YouTube Video https://youtu.be/hfN4VONP4HQ [A1] - Brute Force Time: O(n^2) Space: O(1) class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: for i in range(len(nums)): for j in range(i+1, len(nums)): ...

LeetCode's Valid Anagram problem checks if two strings, `s` and `t`, are anagrams by comparing character frequencies.

Time: O(n^2)
Space: O(1)
class Solution(object):
def containsDuplicate(self, nums):
for i in range(len(nums)):
for j in range(i+1,len(nums)):
if nums[i]==nums[j]:
return True
return False
Comment: Getting TLE in python.
Time: O(nlog(n))
Space: O(1)
class Solution(object):
def containsDuplicate(self, nums):
nums.sort()
for i in range(0,len(nums)-1):
if nums[i]==nums[i+1]:
return True
return False
Comment: We can do better by sacrificing some memory.
Time: O(n)
Space: O(n)
class Solution(object):
def containsDuplicate(self, nums):
hashmap = set()
for n in nums:
if n in hashmap:
return True
hashmap.add(n)
return False
Comment:set() in python is implemented using hash table.